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main.py

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+from py2neo import Graph, Node, Relationship
+import csv
+# 连接neo4j数据库，输入地址、用户名、密码
+graph = Graph("bolt://localhost:7687", auth=("neo4j", "463060687"))
+graph.delete_all()
+# 分别打开四个CSV文件并读取数据
+with open('E:/KG/neo4j-community-3.5.28/import/病例地点行程信息文件.CSV', 'r') as f1:
+    reader1 = csv.reader(f1)
+    data1 = list(reader1)
+with open('E:/KG/neo4j-community-3.5.28/import/病例基本信息文件.CSV', 'r') as f2:
+    reader2 = csv.reader(f2)
+    data2 = list(reader2)
+with open('E:/KG/neo4j-community-3.5.28/import/时间信息文件.CSV', 'r') as f3:
+    reader3 = csv.reader(f3)
+    data3 = list(reader3)
+with open('E:/KG/neo4j-community-3.5.28/import/公共交通工具信息文件.CSV', 'r') as f4:
+    reader4 = csv.reader(f4)
+    data4 = list(reader4)
+# 利用两个FOR_IN循环来获取各个文件中的节点信息
+for i  in  range(1,len(data2)):
+    person = Node('person', name=data2[i][0], severity=data2[i][1], age=data2[i][2], gender=data2[i][3],
+                  confirmed_time=data2[i][4])
+    graph.create(person)  # 构建人物信息节点
+    for j in range(0,30):
+        place=Node('place',name=data1[i][j])
+        date=Node('date',name=data3[i][j])
+        transportation=Node('transportation',name=data4[i][j])
+        graph.create(place)  #构建地点信息、日期信息和交通工具信息节点
+        graph.create(date)
+        graph.create(transportation)
+        # 构建四个类型数据之间的关系
+        graph.create(Relationship(person,'到达过',place))
+        graph.create(Relationship(person,'于',date))
+        graph.create(Relationship(person,'乘坐',transportation))
+        graph.create(Relationship(place,'L',date))
+        graph.create(Relationship(place,'L',transportation))
+        graph.create(Relationship(transportation,'L',date))
+        # 下面三句代码分布实现合并三个类型数据的相同节点操作
+        graph.run(
+            'MATCH (n:place) WITH n.name AS name, COLLECT(n) AS nodelist, COUNT(*) AS count WHERE count > 1 CALL apoc.refactor.mergeNodes(nodelist) YIELD node RETURN node')
+        graph.run(
+            'MATCH (n:date) WITH n.name AS name, COLLECT(n) AS nodelist, COUNT(*) AS count WHERE count > 1 CALL apoc.refactor.mergeNodes(nodelist) YIELD node RETURN node')
+        graph.run(
+            'MATCH (n:transportation) WITH n.name AS name, COLLECT(n) AS nodelist, COUNT(*) AS count WHERE count > 1 CALL apoc.refactor.mergeNodes(nodelist) YIELD node RETURN node')
+
+        #注意在python运行完这段代码后，如果构建的图谱含有空节点，需要到neo4j中进行空节点删除操作
+
+
+
+