94 lines
2.8 KiB
Python
94 lines
2.8 KiB
Python
"""
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题目：给你两个字符串 word1 和 word2 。请你从 word1 开始，通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长，就将多出来的字母追加到合并后字符串的末尾。返回 合并后的字符串。
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示例 1：
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输入：word1 = "abc", word2 = "pqr"
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输出："apbqcr"
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解释：字符串合并情况如下所示：
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word1： a b c
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word2： p q r
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合并后： a p b q c r
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示例 2：
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输入：word1 = "ab", word2 = "pqrs"
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输出："apbqrs"
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解释：注意，word2 比 word1 长，"rs" 需要追加到合并后字符串的末尾。
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word1： a b
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word2： p q r s
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合并后： a p b q r s
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示例 3：
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输入：word1 = "abcd", word2 = "pq"
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输出："apbqcd"
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解释：注意，word1 比 word2 长，"cd" 需要追加到合并后字符串的末尾。
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word1： a b c d
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word2： p q
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合并后： a p b q c d
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"""
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class Solution(object):
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def mergeAlternately_0(self, word1, word2):
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"""
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菜鸟写法：写的好像比较复杂，但是胜在实现了。
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:type word1: str
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:type word2: str
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:rtype: str
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"""
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target = []
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if len(word1) >= len(word2):
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_word1 = word1[:len(word2)]
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_word2 = word2
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_word3 = word1[len(word2):]
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else:
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_word1 = word1
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_word2 = word2[:len(word1)]
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_word3 = word2[len(word1):]
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for i in list(zip(_word1, _word2)):
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target.append(i[0])
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target.append(i[1])
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target.extend(_word3)
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return "".join(target)
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def mergeAlternately_1(self, word1, word2):
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"""
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:type word1: str
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:type word2: str
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:rtype: str
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"""
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target = ""
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if len(word1) >= len(word2):
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_word1 = word1[:len(word2)]
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_word2 = word2
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_word3 = word1[len(word2):]
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else:
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_word1 = word1
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_word2 = word2[:len(word1)]
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_word3 = word2[len(word1):]
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for i in range(len(_word1)):
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target = target + _word1[i] + _word2[i]
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return target + _word3
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def mergeAlternately_2(self, word1, word2):
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"""
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:type word1: str
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:type word2: str
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:rtype: str
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"""
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word_merge = ""
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for i in range(0, min(len(word1), len(word2))):
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word_merge = word_merge + word1[i] + word2[i]
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if len(word1) > len(word2):
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word_merge = word_merge + word1[i + 1:]
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else:
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word_merge = word_merge + word2[i + 1:]
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return word_merge
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def mergeAlternately_3(self, word1: str, word2: str) -> str:
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lw = min(len(word1), len(word2))
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return ''.join(word1[i] + word2[i] for i in range(lw)) + word1[lw:] + word2[lw:]
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